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4^x=(1/2)^x-15
We move all terms to the left:
4^x-((1/2)^x-15)=0
Domain of the equation: 2)^x-15)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4^x-((+1/2)^x-15)=0
We multiply all the terms by the denominator
4^x*2)^x-15)-((+1=0
Wy multiply elements
8x^2+1=0
a = 8; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·8·1
Δ = -32
Delta is less than zero, so there is no solution for the equation
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